Can a table have two primary keys?
Answers were Sorted based on User's Feedback
Answer / suresh babu
No,The Table should have one primary key.But we can create
single primary key for combination of more columns,which is
called Composite Primary Key.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / damini
No.A table can have only one primary key .if it is having
more than one primary key then we say it as composite
primary key...A composite primarykey is a primary key of 2
or more columns together..A composite primary key is
different from primary key..
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / subbarayulu
No, a table should allows only one primary key with the
properties of NOT NULL + UNIQUE . But user can be able to
give more than one primary keys in a table with the help of
NOT NULL and UNIQUE KEYs but not directly using PRIMARY KEY
constraint.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / srilekha
no,it's not possible to set more than one primary key column
to a single table
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sattprakash mittal
Primary key is a field which is uniquely identified each record in a table. A table can only one primary key but there are more field can be used as primary key are known as candidate keys
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / pardeeep
NO,A table have only one primary key.But we can use it on more then one column.
Exp..
create table emp(empno int,ename nvarchar(20),deptno int,constraint Pk_constraint primary key( empno,deptno))
This query for SQL server
| Is This Answer Correct ? | 1 Yes | 0 No |
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Dear All, Question for this Week Find out possible error(s) (either at compile time or at runtime) in the following PL/SQL block. State the reason(s) and correct the errors. Declare Cursor C1 is select ename, sal, comm from emp; Begin For i in C1 Loop If i.comm between 299 and 999 then Dbms_output.put_line(i.Ename || ‘ ** Good Commission’); Elsif i.comm > 999 then Dbms_output.put_line(i.Empno || ‘ ** Very Good Commission’); close C1; Else Dbms_output.put_line(i.Ename || ‘ ** ’ ||nvl(i.comm,‘O’)); End if; End Loop; End;
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