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A starts from a place at 11.00 am and travels at a speed of
4 kmph , B starts at 1.00 pm and travels with speeds of 1
kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the
next hr and so on. At wht time will B catch up with A ?
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Answer / dolly
n(n+1)/2-8=4(n-2) is the equation
and they will meet sameday at 8:00pm
| Is This Answer Correct ? | 2 Yes | 13 No |
Answer / ajeet
Ans 9.8150 PM on same day
Basically
equation will be like this::
n(n+1)/2=8+4n
and it will give the value
n=8.8150
| Is This Answer Correct ? | 2 Yes | 13 No |
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