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2hours after a freight train leaves Delhi a passenger train
leaves the same station travelling in the same direction at
an average speed of 16 km/hr. After travelling 4 hrs the
passenger train overtakes the freight train. The average
speed of the freight train was?
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Answer / manish yadav
distance covrd in 4 hrs by passngr trn=16*4=64km
same distnc is covrd by fright trn in 4+2 hrs i.e 6 hrs
so speed of frieght trn=64/6=10.66 km/hr
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / shelly
The passenger train travels (16 km/hr)(4 hr) = 64 km
The freight train has traveled the same distance, but in a
total of 6 hours. Use the formula d=rt and solve for r:
64 km /6 hr = 10 2/3 km/hr. Written as a decimal would be
10.666666666......
Ved was on the right track,but rounded the hundredths place
to 7 before adding the ,,,,,,,,,,, which makes it appear
that the 7 was repeated rather than the 6.
Those are some slow trains!!
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / ragu
Same problem that i faced in an interview......NO ANSWER FOR THIS QUESTION IN ANY DIMENSION .SoThe question is wrong .DECLARED
| Is This Answer Correct ? | 5 Yes | 2 No |
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