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The LCM of two numbers is 2079 and their HCF is 27. If one
of the numbers is 189, find the other number.
(a) 248
(b) 128
(c) 297
(d) 336
(e) None of these
- 12 Answers
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Answer / suchi teegala
given lcm of 2 numbers is 2079
and hcf of the 2 numbers is 27
their is a rule as
lcm=(product of numbers )/hcf
given one number as 189
let the other number be x
therefore , 2079=189x/27
on solving x= (2079*27)/189
we get x= 297 which is the answer
| Is This Answer Correct ? | 153 Yes | 13 No |
Answer / varun
formula to find other number is
LCM * HCF = 1st no. * 2nd no.
hence, 2079 * 27 = 189 * X
X = (2079 * 27) / 189
X = 297
| Is This Answer Correct ? | 80 Yes | 12 No |
Answer / rohan
First prime factorise both LCM and HCF.
LCM=2079=7x3x3x11x3
HCF=27=3x3x3
So cut of the common numbers between the LCM and HCF that gives us 11 and 7 in LCM.
Now multiply the HCF with both the numbers(separately).
One number is 27x7=189(the number provided)and the other number is 27x11=297.This is my answer.
| Is This Answer Correct ? | 35 Yes | 4 No |
Answer / prem
we have a formula like
product of two numbers=lcm*hcf=>a*b=lcm*hcf
given lcm=2079 hcf=27 a=189
.
. .b=(2079*27)/189=297
| Is This Answer Correct ? | 24 Yes | 7 No |
Answer / gaurav yadav
Product of two numbers = Their H.C.F * Their L.C.M
189 * X = 2079 * 27
Therefore X = (2079 *27)/189
= 297
| Is This Answer Correct ? | 8 Yes | 1 No |
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