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The LCM of two numbers is 2079 and their HCF is 27. If one
of the numbers is 189, find the other number.
(a) 248
(b) 128
(c) 297
(d) 336
(e) None of these
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Answer Posted / rohan
First prime factorise both LCM and HCF.
LCM=2079=7x3x3x11x3
HCF=27=3x3x3
So cut of the common numbers between the LCM and HCF that gives us 11 and 7 in LCM.
Now multiply the HCF with both the numbers(separately).
One number is 27x7=189(the number provided)and the other number is 27x11=297.This is my answer.
| Is This Answer Correct ? | 35 Yes | 4 No |
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