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How many such pairs of letters are there in the word
STAINLESS each of which has as many letters between them in
the word as they have in the English alphabet, in the same
sequence?
(a) Two
(b) Three
(c) Four
(d) Five
(e) None of these
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Answer / guest
can u please make me understand the question please reply
back
| Is This Answer Correct ? | 28 Yes | 22 No |
Answer / karthik
preeti is great ..perfectly understood..i have another doubt..
the question is,,
some pens are sticks
some sticks are scales
all canes are scales
no scale is weight...
i understood about the "A,E,I" type conclusions..but stil
some answer that i presict are wrong..i understood by
myself..can u please help me more to understand more
| Is This Answer Correct ? | 9 Yes | 3 No |
Answer / samuel
how are we supposed to take the pairs,
i have seen the pairs smtimes are in
reverse order in books but they hardly
explain them, for instance there are
eight alphabets being used in the word
"stainless". and why cant we take pairs
like sn, ai le nl es etc? whoevr answers
me would be doing me a grt favour,
thanks in advance
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / veera
how many such pairs of letters are there in the
word "SYSTAMATIC" each of which has as many letters between
them in he word as in the english alphabet?
plz tell me answer and explain.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / pradeep k s
Answer is (e)
From the word STAINLESS we can observe that
1. No of letters between A and E i.e 3 (INL) which is
similar no of letters present in english alphabet
AINLE -----(1)
ABCDE -----(2)
from 1 & 2 INL replaces BCD
2. No of letters between I and E are two in reality No of
letters present between I and e are 3 i.e FGH its not possible
so answer is (e)
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / brahma
How many such pairs of letters are there in the word
TERMINATE each of which has as many letters between them in
the word as in the English alphabet ?
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / nellaiappan. s
AINLE ---> ABCDE
There is only one pair.So the answer is one. But from this given options in option (e)is the better
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vivek_jack
actually i think its 3
caz
method:
select 1st letter
s COUNT THE NEXT WORD IN THE ALPHABET AND THEN SEE THE GIVEN WORD ( IN ALPHABET T COMES AFTER s AND NW LOOK AT WORD GIVEN )IN THE GIVEN WORD ALSO T COMES AFTER S SO
COUNT IS 1
AND NEXT COUNT THE NEXT WORD IN ALPHABETS S->T->U BUT ITS NOT MATCHES IN THE GIVEN WORD SO COUNT IS STILL 1
SO GO ON LIKE THAT
WHILE UR TAKING THE LETTER A THEN A-B-C-D-E
AND GIVEN WORD IS A-I-N-L-E
SO MATCHED
GO ON LIKE THAT ALPHABET: NL
WORD : NL
SO COUNT IS 3
FOR PEOPLE WHO ASKED PROCEDURE
MY PROCESS IS THAT IF ANY EASY ONE IS THERE U CAN POST .....
ITS EASY CAZ WE CAN DO THAT JUST WID OUR EYES
| Is This Answer Correct ? | 0 Yes | 0 No |
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