ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.30 : A biochemical engineering sales contract adopts Cost Recovery Method in its company accounting. Gross profit is realised only when cash collections exceed the total cost of goods sold. Let Y = Original Cost Recovered, Z = Gross Profit Realised. Its property was sold at A = $500k with cost of B = $300k. Its engineering accountant receives cash of C = $240k in first year, D = $180k in second year and E in third year. (a) Find the values of Y and Z in : (i) first year; (ii) second year; (iii) third year. (b) What is the exact value of E if all cash has been fully received from sales?
ACCOUNTING AND FINANCIAL ENGINEERING - ANSWER 34.30 : (a)(i) First year : Y = C = $240k, Z = 0 (since C < B). (ii) Second year : Y = B - C = $300k - $240k = $60k, Z = C + D - B = $240k + $180k - $300k = $120k [ since (C + D) > B ]. (iii) Third year : Y = 0, Z = E. (b) E = A - C - D = $500k - $240k - $180k = $80k. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
Is This Answer Correct ? | 0 Yes | 0 No |
did sulphur been a byproduct after the combustion of LPG and Natural Gas
What particle sizes are electrostatic precipitators used to remove?
Question 37 - Calculate the bubble temperature T at P = 85-kPa for a binary liquid with x(1) = 0.4. The liquid solution is ideal. The saturation pressures are Psat(1) = exp [ 14.3 - 2945 / (T + 224) ], Psat(2) = exp [ 14.2 - 2943 / (T + 209) ] where T is in degree Celsius. Please take note that x(1) + x(2) = 1. Please take note that y(1) + y(2) = 1, y(1) = [ x(1) * Psat(1) ] / P, y(2) = [ x(2) * Psat(2) ] / P, * is multiplication. P is in kPa.
What is carbon sequestration?
What are some common problems associated with bellow expansion joints?
Tell us about a time when you failed to meet a deadline. What were the repercussions?
4 Answers Bhavani Engineering Works, Caltex, Emirates, Holiday Inn, Regent, United States Seafoods,
CHEMICAL FLUID MECHANIC - EXAMPLE 3.1 : Water flows through a pipe with circular cross sectional area at the rate of V / t = 80 L / s where V is the volume and t is time. Let Av = 80 L / s where A is cross sectional area and v is velocity of fluid. For point 1, the radius of the pipe is 16 cm. For point 2, the radius of the pipe is 8 cm. Find (a) the velocity at point 1; (b) the velocity at point 2; (c) the pressure at point 2 by using Bernoulli's equation where P + Rgy + 0.5 RV = constant. P is the pressure, R = density of fluid, V = square of fluid's velocity, g = gravitational constant of 9.81 N / kg and y = 2 m = difference of height at 2 points. The pressure of point 1 is 180 kPa.
Oil and fat containing food items are flushed with nitrogen. Why?
What is an isochoric process?
i am a student of thapar university final year.can anybody please help me with the exam pattern of the companies:engineers india ltd. ; iocl ; UOP, HPCL. If psbl plz send me the previous years questions on this email id k_arora1987@yahoo.com. i d be really greatful
distance education chemical engineer degree aprooved courses any?
Explain the difference between cfm (cubic feet per minute) and scfm (standard cubic feet per minute)?