did sulphur been a byproduct after the combustion of LPG
and Natural Gas
Answers were Sorted based on User's Feedback
Answer / m v mehta
No, normally sulphur is removed by desulphurizer before
taking natural gas in process. So, there are no chances of
sulphur as by product after the combustion of LPG and
Natural Gas.
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Answer / kln
There are less chances of presence of Sulfur in LPG/NG and
even if it presents no matter that sulfur will be in the
form of residual sulfur after combustion of LPG/Natural Gas
it will convert to SO2
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Question 63 – Autocad computer program is used to draw a pipe that is used to transport natural gases for processing. Actual length of the pipe is 10 metres. The pipe has cross sectional area of circle in shape with measured circumference of s = 3 metres. (a) If 10 units are used to represent the actual length of the pipe in computerised engineering drawing, find the diameter of the pipe, d that will be shown in the engineering drawing. (b) If one unit in the program equals to 1 centimetre, find the scale used in the computer program.
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Water flows through a pipe with circular cross sectional area at the rate of V / t = 80 L / s where V is the volume and t is time. Let Av = 80 L / s where A is cross sectional area and v is velocity of fluid. For point 1, the radius of the pipe is 16 cm. For point 2, the radius of the pipe is 8 cm. Find (a) the velocity at point 1; (b) the velocity at point 2; (c) the pressure at point 2 by using Bernoulli’s equation where P Rgy 0.5 RV = constant. P is the pressure, R = density of fluid, V = square of fluid’s velocity, g = gravitational constant of 9.81 N / kg and y = 2 m = difference of height at 2 points. The pressure of point 1 is 180 kPa.
sir i am appearing in railway exam of section engineer and my branch is chemical engineering i want previous question paper of section engineer of chemical branch please tell me as soon as possible my email id is surendrasaroj18@gmail.com THANKYOU
CHEMICAL MATERIAL BALANCE – EXAMPLE 2.2 : Three hundred gallons of a mixture containing 75.0 wt % ethanol and 25 wt % water (mixture specific gravity = 0.877) and a quantity of a 40.0 wt % ethanol - 60 wt % water mixture (specific gravity = 0.952) are blended to produce a mixture containing 60.0 wt % ethanol. The specific gravity of a substance is the ratio of density of a substance compared to the density of water. The symbol of weight percent is wt %. (a) Estimate the specific gravity of the 60 % mixture by assuming that y = mx c where y is wt % ethanol, x is mixture specific gravity. Values for m and c are constants. (b) Determine the required volume of the 40 % mixture.
UNIT OPERATION - EXAMPLE 9.1 : Which of the sequence below represent a feasible flows of ethanol processing plants using cellulose as starting material? A. raw material -> heat exchanger -> distillation column -> reactor. B. reactor -> distillation column -> raw material -> heat exchanger. C. heat exchanger -> raw material -> distillation column -> reactor. D. raw material -> heat exchanger -> reactor -> distillation column. E. distillation column -> raw material -> reactor -> heat exchanger.
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