In a triple effect evaporator, the heat transfer for an evaporator is calculated as q = UA (TI – TF) where TI is the initial temperature, TF is the final temperature; U and A are constants. Given that heat transfer for the first evaporator : q(1) = UA (TI – TB); second evaporator : q(2) = UA (TB – TC); third evaporator : q(3) = UA (TC – TF) where q(x) is the heat transfer function, TB is the temperature of second inlet and TC is the temperature of third inlet, prove that the overall heat transfer Q = q(1) q(2) q(3) = UA (TI – TF).
Answer / kang chuen tat (malaysia - pen
Answer 12 : Q = q(1) + q(2) + q(3) = [ UA (TI – TB) ] + [ UA (TB – TC) ] + [ UA (TC – TF) ] = UATI + (UATB – UATB) + (UATC – UATC) – UATF = UATI – UATF = UA (TI – TF) (Proven). The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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respected sir,i have been selected in the written examination prelim (CHEMICAL) of RINL(RASHTRIYE ISPAT NIGAM LTD.) held on 20 JUNE, So please tell me which type of questions will be asked in 2nd stage written exam. plz send me last 2-3 years questions asked in RINL(written exam).
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