A wattmeter is marked 15 A/30A, 300V/600V and its scale is marked up to 4500 watt. When the meter is connected for 30A, 1600V, the pointer indicates 2000 watts. The actual power in the circuit in
Answer / sudip saren
Power consumed(wattmeter)=ct ratio*pt ratio*vi*cos$
2000=(15/30)*(300/600)*600*30*cos$
or, cos$=0.44
P actual=VIcos$=600*30*0.44=8000w
| Is This Answer Correct ? | 46 Yes | 8 No |
hi friends this is a newcomer in your community of enthusiastic peoples. i am preparing for SSC (CPWD JUNIOE ENGG EXAM FOR ELECTRICAL) pls guide me on the same how to crack it? PLS LET ME KNOW IS ANYONE THERE WHO PASED IT? CAN I GET THE QUESTION PAPERS OF PREVIOUS EXAMINATIONS?
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