Answer / asit

i=sqr3 E20/sqr(R20+iX20)

Answer / ajai shukla

It depends upon that motor is under load condition for mechanical free.
If motor is under load then I will take 2 to 3 times of full load current. Keep in mind that motor is running in DOL starter.
Under no mechanical coupling it will take 1.5 times of full load current.

Answer / h s sandhu

1.5 times the full load current of the motor. That is why reduced voltage is applied initially in star /delta starter to reduce starting current 

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