Answer / sfz ans

Assume size of bricks = 0.19m x .09m x .09m

therefore size of bricks with mortar (assuming 20mm of mortar filling betn two bricks ie: each brick gets 10mm thick layer of mortar at their face) = 0.2m x 0.1m x 0.1m

now divide the area depending upon the type of masonary work ie: Streching bond, flemish bond etc

eg:
Streching Bond for 10 sqm

no. of bricks = 10/(0.2*0.1) = 500 bricks.


Streching Bond for 1 cum work

no. of bricks = 1/(0.2*0.1*0.1) = 500 bricks

Answer / srikanth

Normally the size of the brick is 9"x3"x4" so,we can convert into feet is 0.75x.25x.33=0.061.
1)35.28/0.061=578no.s of brick for 1Cum
2) But we have to deduction of the Mortar from it so,20% of the Mortar we can deduction forn the 578 bricks the total no.of bricks is 462 no.s

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