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A 4 digit no may consist of the digits 6,2,7,5 where
none of the nos are repeated.Find the possible no of
combinations divisible by 36?
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Answer / v.n.dubey
the 4 digit numbers that will be formed from ( 6,2,7,5)with
no repetition, can not divisible by 36.
because these no. must be divisible by 6.
A no. will be divisible by 6 when it is also divisible by 2
and 3.
so some of these formed no. divisible by 2 ( eg.7562,5726
etc) but not divisible by 3
becase ( 7+5+6+2)=20 { according to divisibility check}
which is not multiple of 3.
| Is This Answer Correct ? | 11 Yes | 1 No |
Answer / anumod
no combinations is there because a number divisible by 36
also divisible by its divisors anu.sum of 4 digits=20,whis
is not multiple of 3.so it is cannot divisible by 3
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / roshan
A DIGIT TO BE DIVISIBLE BY 36 SHOULD BE DIVISIBLE BY 4 AND
9..A NUMBER TO BE DIVISIBLE BY 9..SUM OF THE DIGS SHOULD BE
DIVISIBLE BY NINE SINCE THE SUM OF DIGITS IS 20 IT CANT BE
DIVIDED BY 9 SO ANSWER IS 0
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / lava kumar
The multiples of 36 are 36,72,108,114,180..
the last digits are 6,2,8,4,0
The given numbers are 6,2,7,5
Therefore they are 2 cases The last digit either can be
accopied by 6 or 2 in 2c1 ways
The first 3 digits in 3! ways
Therefore the number of possible ways is 3!*2c1=12
Hope Iam rite.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / vandana
No
36 is divisible by 6&2
So there are chances obtainging no divisible to 36 by 2ways
10place digit obtain 3ways
100place digit obtain 2 ways
1000place digit obtain 1ways
=2*3*2=12
=12
| Is This Answer Correct ? | 4 Yes | 1 No |
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