why Copper loss is represented as I square R ?
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Answer / anshul pal
Because these are the losses which occur in lines and cause real power loss, hence these loss can not occur in negative term. As current varies sinusoidally, the square of current will remain positive, therefore accounts to i square r loss.
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Answer / md tarekul alam
Pls dear sir, answer me in this question.
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Pd across a resistor id I(amp) x R (ohm) volts ,power is V X
I = I^2 R watt
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Read above as ' Pd V across a resistor= I(amp) x R (ohm)
volt.Power = V x I = I^2 R watt' ( As pd is measured across
the resistor ,the pf is unity)
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