How to swap two variables, without using third variable ?
Answers were Sorted based on User's Feedback
Answer / deep
let a=5 , b=10
a=a-b
means a=5-10=-5
b=b+a
b=10+(-5)
b=5
a=b-a
a=5-(-5)
a=10
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / d maniteja
let
a=x, b=y our aim is to get output as a=y&b=x;
program:
void main()
{
int a=x,b=y;
a=(a+b)+(a-b);
b=(a+b)-(a-b);
a=a/2;
b=b/2;
printf(("%d %d",a,b);
}
| Is This Answer Correct ? | 0 Yes | 1 No |
without using third variable swap two nos
a=(a+b)-(b-a);
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / gobinath
swap(int *a,int *b)
{
*a=*a-*b;
*b=*a+*b;
*a=*b-*a;
}
| Is This Answer Correct ? | 0 Yes | 1 No |
int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().
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main() { printf("%x",-1<<4); }
how to swap 3 nos without using temporary variable
int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().
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main() { int c=- -2; printf("c=%d",c); }
C Code 
