Answer / anil

173.60.40.0/20
s
subnet: 255.255.240.0
So, we have 4bits in 3rd octet. It means 16.
Try to divide the 40/16.
40 is not divisible by 16 it means it's a valid Ip.
So., the netork id would be 16*2=32.
173.60.32.0/20 is the network ID.

Answer / prabhu

u can find the network Id by starting ip ranges
A class 0-127 network id 255.0.0.0
b class 128-191 network id 255.255.0.0
c class 192-223 network id 255.255.255.0

Answer / divyng acharya

first identify network bits from the given mask.make all
the host bits 0.keep the network bits as it is. you obtain
your network address

Answer / mayur

we can find the network id from ip subnet.suppose if we
take 173.16.20.0/20 .The subnet mask will be 255.255.240.0
the subneting is done in the 3rd octet so,if you
substract 256-240 = 16. 16+16=32 .20 comes in between
16 to 31 the network ip will be 173.16.16.0 as the last
ip i.e 32 is considerd as broadcast ip it is not
considered

Answer / krishna

Ithink u didnt understand my question,what i am try to say
is from 173.60.40.0/20 ip address,how will u find network id?

Answer / mukesh thakur

U CAN FIND NETWORK ID BY 1ST OCTET OF IP ADDRESS IN IPV.4
CLASS A RANGE START FROM 0-127,
CLASS B 128-192
CLASS C 192-223
CLASS D USED FOR MULTICAST
CLASS E USED FOR EDUCATION AND RESEARCH
AND 127.0.0.1 IS USED FOR LOOP BACK ADDRESS

Answer / fun e

We can find the network ID from Ip using subnet.Suppose if
we take 192.168.20.0/20.
Now subnet is 255.255.240.0
Here we have 2 full octates and 4 bits in 3rd octet
position.I.e 16.
So the networks will come like this
192.168.1.0
192.168.16.0
192.168.32.0.....
Our ip address 192.168.20.0 is in 192.168.16.0 network.So
192.168.16.0 is the network ID.

Answer / mukesh

this is ur class B ip address because we check it from 1st
octet and 173 is comes between class b 128-191..
so u can check it from 1st octet
in class a 1 network id and 3 host id
in class b 2 network id 2 host id
in class c 3 network id 1 host id

Answer / kis

we can find the network id from ip subnet
suppose ip address is 192.16.20.0/20
subnet mask will be 255.255.240.0
as you can see three bytes are easy to determine.but second
byte need bit-wise AND operation.if two bits are both (1s)
the result will be (1)otherwise result will be zero.
write 20 and 240 in decimal form
128 64 32 16 8 4 2 1
20 : 0 0 0 1 0 1 0 0
240 : 1 1 1 1 0 0 0 0
----------------------------
16 : 0 0 0 1 0 0 0 0

Answer / cibin albin

the network id will be the first ip address of a particular
host ip address.For example if take ip address as
192.168.20.10 then the network address orNetwork ID will be
192.168.20.0

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