Answer / vishwa theja c

the question is (1-s)/(1+s) at 1 rad/sec
the gain is 1 as convert it to rectangular form you will get
square root of 2/ square root of 2 so it is 1. the gain is
inverse of value .so it is 1 only. if it is asked
particularly in db then we get 0.

Answer / ngarjuna

it is an all pass filter(anti symmetric pole zero pattern)
always magnitude is 1 so logarithm of 1 is 0 dB

Answer / sushant

This system is
unstable as t
tends to
infinite its
value goes to
infinite.

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