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Let C be a circle with centre P0 and AB be a diameter of C.
Suppose P1 is the mid point of the line segment P0B, P2 is
the mid point of the line segment P1B and so on. Let C1, C2,
C3, ...... be circles with diameters P0P1, P1P2, P2P3 ...
respectively. Suppose the circles C1 C2, C3, .... are all
shaded. The ratio of the area of the unshaded portion of C
to that of the original circle C is
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Answer / hitesh
let PI is x
then
let area of whole circle is xr*r where r is radius of circle.
then according to this, area of c1 is (xr*r)/4
similarly area of c2 is (xr*r)/16
and area of c3 is (xr*r)/64
add all these area that is 21(xr*r)/64
this is shaded portion.
Now the ratio of shaded portion to the original circle is (21(xr*r)/64)/xr*r
Ans = 21/64
| Is This Answer Correct ? | 3 Yes | 13 No |
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