Answer / baljinder singh

According to I=V/R. The resistance of 40W bulb is high than
100W bulb , but current flowing in it low rather than 100W
bulb. The Power= I^2R. The current is multiply with own
first ,because it has square ,and then it multiply with
voltage. So when current is decrease the power is consume by
bulb is less..

Answer / joydeep kr. chakraborty

The Joule's formula P=I^2R holds good only if I through
them is Constant. But, when connected accross same voltage,
the current through a 40W bulb is less than a 100W bulb.
Thus, I^2R for 40W bulb will be much much less than that of
a 100W bulb.
If we connect them in SERIES and apply voltage to the
combination, the current passing through them will be same,
and in that case, the 40W bulb will definitely CONSUME MORE
POWER THAN 100W BULB.

Answer / osho katyal

In domestic lines,we got parallel connections. So formula
P=V2/R is applicable .As such P and R are inversely related.
So power less more resistance less cureent.

Answer / kiran

even if u take the resistance of 40 watt bulb higher than
100 watt bulb,as the current varies square(I^2) the power
consumption,so power consumed by 100 watt is higher than
former........

Answer / manda.gopal1

I think that 40 watt bulb has more impidence then 100 watt
bulb. 40 watt bulb offer higher impedence then 100 watt bulb

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