Answer / guest

(1/(0.2*.1*.1))=500

=500*(.19*.09*.09)=0.76 cum of brick volume

=1-.76 = 0.24 mortor volume
=0.24

Answer / anandh kumar g

first we have to find out the CM ration after thatonly we
can able to finout the cement content

Answer / mohammed aijaz hussain

Volume of Dry Mortar = 35% of volume of Brickwork

Let the Cement Mortar Proportion be CM(1:4)

Volume of mortar required = 0.35 X 1 = 0.35 cu.m.

Cement required = 1/5 X 0.35 = 0.07 cu.m. = 2 bags

Sand required = 4/5 X 0.35 = 0.28 cu.m.

Answer / gowtham1993

(1/(0.2*.1*.1))=500

=500*(.19*.09*.09)=0.76 cum of brick volume

=1-.76 = 0.24 mortor volume
=0.24
so
for 1:4 cement mortor it require 1% cement and 4% sand

0.06 cu.m of sand is required

Answer / paramesh

25% 0f mortar in 1cum of 230 thick brick wall.
(ie) 0.25cum of mortar.calculate the cement content by its
ration.

Answer / sri

volume occupied by brick=100x.19x.09x.09=.153cu.m
volume of brick 1x1x.23=.23cu.m

volume of joints=0.23-0.153=0.077cu.m
mortar to fill up frogs=100x.10x.04x.01=.004cu.m
total mortar=.077+.0040=0.081cu.m

Answer / muhammad saleem

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