Answer / susie

Answer :

hello 5

Explanation:

if you declare i as register compiler will treat it as
ordinary integer and it will take integer value. i value may
be stored either in register or in memory.

Answer / sandeep

answer


hello 5

printf("%s",j); printf hello because j is a array it also
contain base address of first element of array .


register i treate simple integer

void ( * abc( int, void ( *def) () ) ) ();

1 Answers  

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main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

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writte a c-programm to display smill paces

2 Answers  

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main() { extern int i; i=20; printf("%d",i); }

1 Answers   Value Labs,

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main() { printf("\nab"); printf("\bsi"); printf("\rha"); }

3 Answers  

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4. Main() { Int i=3,j=2,c=0,m; m=i&&j||c&I; printf(“%d%d%d%d”,I,j,c,m); }

2 Answers   Broadridge,

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#ifdef something int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }

1 Answers  

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char *someFun1() { char temp[ ] = “string"; return temp; } char *someFun2() { char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’}; return temp; } int main() { puts(someFun1()); puts(someFun2()); }

2 Answers  

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d----%d",*p,*q); }

1 Answers  

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PROG. TO PRODUCE 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1

1 Answers  

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Under linux environment can u please provide a c code for computing sum of series 1-2+3-4+5......n terms and -1+2-3+4-5...n terms..

2 Answers  

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