Answer / susie

Answer :

0 0

Explanation

This code is to show that preprocessor expressions are not
the same as the ordinary expressions. If a name is not known
the preprocessor treats it to be equal to zero.

main() { float f=5,g=10; enum{i=10,j=20,k=50}; printf("%d\n",++k); printf("%f\n",f<<2); printf("%lf\n",f%g); printf("%lf\n",fmod(f,g)); }

1 Answers  

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main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

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Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.

5 Answers   IITR, Microsoft, Nike,

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void main() { static int i=i++, j=j++, k=k++; printf(“i = %d j = %d k = %d”, i, j, k); }

3 Answers  

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What is wrong with the following code? int *foo() { int *s = malloc(sizeof(int)100); assert(s != NULL); return s; }

1 Answers  

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main() { if ((1||0) && (0||1)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

5 Answers   HCL,

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int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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main() { char * strA; char * strB = I am OK; memcpy( strA, strB, 6); } a. Runtime error. b. I am OK c. Compile error d. I am O

4 Answers   HCL,

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main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

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Write a procedure to implement highlight as a blinking operation

2 Answers  

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Find the largest number in a binary tree

7 Answers   Infosys,

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