Answer / priti rachana

#include<stdio.h>
#include<conio.h>
void main()
{
int p,q,m,n,c;
int a1[100],a2[100],a3[100];
puts("enter the number of elements of the 1st sorted array");
scanf("%d",&p);
puts("enter number ofthe 1st sorted array");
for(m=0;<=p-1;m++)
scanf("%d",&a1[m]);
puts("enter number of element of the 2nd sorted array");
scanf("%d",&q);
puts(enter element of the 2nd sorted array");
for(n=0;n<=q-1;n++)
scanf("%d",&a2[n]);
c=0;
m=0;
n=0;
while((m<p)&&(n<q))
{
if(a1[m]<=a2[n])
a3[c]=a1[m++];
else
a3[c]=a2[n++];
c++;
}
while(m<p)
{
a3[c]=a2[n];
c++;
n++;
}
puts("merged array in asending order");
for(m=0;m<=c-1;m++)
printf("%d\n",a3[m]);
}

puts("enter the number of elements in the 2nd sorted arra array");
scanf("%d",&q);

Answer / ashok kannan

#include<stdio.h>
void main()
{
int a[]={1,1,2,3,4,5},b[]={2,3,4,5,6};
int i,j;
for(i=0;a[i]!='\0';i++);

for(j=0;b[j]!='\0';j++)
{
a[i]=b[j];
i++;
}

for(i=0;a[i]!='\0';i++)
printf("%d",a[i]);

}

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