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three friends a,b,c run around a circular track of length
120m at a speed of 5,7,15m/sec respectively starting
simultaneously from the same point in the same
direction .how often they three will meet????
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Answer / thilak desingh
Guys, there can be two ways of interpreting,
1) How often they meet at any point
2) How often they meet at starting point
1) LCM { L/a-b , L/b-c} = 60 seconds
2) LCM { L/a , L/b , L/c } ~ 120 seconds
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / manish pal
Soln: When two people are running in the same direction the relative speed is the difference in speeds of the two people.
In this case A=5 B=7 C=15
So relative speed of B wrt A is 7-5 = 3m/s
Relative speed of c wrt to a is 15-3 =15m/s
Therefore relative distances will be:
B wrt A is 120/2 =60
C wrt to A 120/12 =12
So they have to bridge this distance of 60 and 12 between them which is the LCM of 60 and 12 which is 60.
so ans is 60 sec
| Is This Answer Correct ? | 4 Yes | 5 No |
Answer / nisha
Time taken by 'a' to cover a circular track = 120/5 = 24
seconds
Time taken by 'b' to cover a circular track = 120/7 seconds
Time taken by 'c' to cover a circular track = 120/15 = 8
seconds
LCM of 24, 8, 120/7 = 120/7seconds = ~ 17 seconds
So the three friends will meet after ~17 seconds
| Is This Answer Correct ? | 6 Yes | 11 No |
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