using repetition structure. Write a c program that will
accept five numbers. The program should count and output the
total count of even numbers and total count of add numbers.
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Answer / abikrishna
#include <iostream>
using namespace std;
int main ()
{
int a[6],i,ec=0,oc=0;
for(i=0;i<5;i++)
cin>>a[i];
for (i=0;i<5;i++)
{
if (a[i]%2==0)
ec++;
else
oc++;
}
cout<<"\t Even Count is : "<<ec;
cout<<"\t Odd Count is : "<<oc;
return 0;
}
| Is This Answer Correct ? | 22 Yes | 9 No |
Answer / john
#include <iostream>
using namespace std;
int main(){
int array[5];
int i;
int evens = 0;
int odds = 0;
for(i = 0; i < 5; i ++){
cout << "Enter number: ";
cin >> array[i];
if(array[i] & 1)
odds++;
else evens++;
}
cout << "\nEvens: " << evens;
cout << "\nOdds: " << odds;
}
| Is This Answer Correct ? | 7 Yes | 9 No |
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