Answer Posted / abikrishna

#include <iostream>
using namespace std;



int main ()
{
int a[6],i,ec=0,oc=0;
for(i=0;i<5;i++)
cin>>a[i];

for (i=0;i<5;i++)
{
if (a[i]%2==0)
ec++;
else
oc++;
}
cout<<"\t Even Count is : "<<ec;
cout<<"\t Odd Count is : "<<oc;

return 0;
}

output for printf("printf");

2199

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