Answer / ruchi

#include<stdio.h>
#include<conio.h>
int main()
{
int i,p;
printf("\nNumbers are ");
for(i=1000;i<=9999;i++)
{
p=(i*i);
if(p%2==0)
{
printf("%d\n",i);
}
}
getch();
}

Answer / abdur rab

Any even number squard will yield an even value

#include <stdio.h>

int main ( int argc, char* argv [] )
{
int nloop = 0;
for ( nloop = 1000; nloop < 10000; nloop++ ) {
if ( ( nloop ) % 2 == 0 ) {
printf ("\n The Number is : %d",
nloop );
}
}
return ( 0 );
}

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