Write a C program that reads a series of strings and prints
only those ending in "ed"
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Answer / mani
#include<stdio.h>
main()
{
char *a[6]={"sayed","jhsdj","manvi","buged","error"};
int i,j,k,h;
int flag=0;
for(i=0;i<5;i++)
{
j=0;
j=strlen(a[i]);
if(*(a[i]+3)=='e'&& *(a[i]+4)=='d')
{
printf("%s\n",a[i]);
}
else
{
printf("no match\n");
}
}
}
| Is This Answer Correct ? | 11 Yes | 11 No |
Answer / antony from chennai
void main()
{
char *s[10];
int n;
printf("No of strings:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%s",s[i]);
}
for(i=1;i<=n;i++)
{
int len;
len=strlen(*s[i]);
len=len-1;
if(*s[len]='e' && *s[len--]='d')
{
printf("%s",*s[i]);
}
else
{
printf("no match");
}
}
getch();
}
}
| Is This Answer Correct ? | 4 Yes | 16 No |
a number whose only prime factors are 2,3,5, and 7 is call humble number,,write a program to find and display the nth element in this sequence.. sample input : 2,3,4,11,12,13, and 100.. sample output : the 2nd humble number is 2,the 3rd humble number is 3,the 4th humble number is ,the 11th humble number is 12, the 12th humble number is 14, the 13th humble number is 15, the 100th humble number is 450.
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