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what is the difference between BVA&ECP?

Answers were Sorted based on User's Feedback



what is the difference between BVA&ECP?..

Answer / naresh

These two menthods are useful to minimize the test cases.
These two methods are looking very simillar

In BVA(Boundary Value Analysis) we can check the the
boundaries values min-1, min, middle value(optional), max,
max+1
For example: If the boundary value for a field is between 1
to 98 , we can check with the values 0,1, any of the value
between 1 to 98 , 98 and 99


please let me know if i'm not correct


but in Equivalece Class Partioning we should check the
condition with different values from three partitions like
we should take some values in the positive partition and
take some values from negative partitions. For example take
the above example here the positive partition is the range
beteween 1 to 98, the negative partitions are o to -97 and
99 to 196.

see in the BVA we are not checking with the minus values
like -1, -2, -3 we can't say it can't take minus values and
also we are not checking with the three digit numbers in
the BVA, but here we have scope to check the three digit
values also as well

Is This Answer Correct ?    3 Yes 0 No

what is the difference between BVA&ECP?..

Answer / ratha .a

Boundary value analysis and equilance class partioning are
the testcase design techniques.

EQUILANCE CLASS PARTIONING:
ECP is a method for deriving the test cases.in this
method idetified that each member of the class causes the
same kind of proceesing and output to occur.Based and the
characteristics classes are formed in valid and invalid
classes.

BOUNDARY VALUE ANALYSIS:
Testing at the two boundaries.

0-40:F
41-50:D

-1,0,1,39,40,41:F
40,41,42,49,50,51:D

Is This Answer Correct ?    0 Yes 0 No

what is the difference between BVA&ECP?..

Answer / rudraneel

BVA :

Boundary Value Analysis :

1.It is a Black Box Technique
2.Here input values for boundaries of input domain are
tested.
3.Here valid and invalid both values are considered.

Example :
For a login page SRS is

UserId should be within 15-50 characters
so valid boundaries are 15-50
invalid boundaries are <15 or >50 i.e; 14 or 51
If A(Valid)=15/50 thenA1(Invalid)=14/51
For Invalid Boundaries always considered like this way (A-
1) or (A+1)

Adv:
>Very good at exposing potential input problems
>very clear guide-lines on determining test cases
>Very small set of inputs are generated

Disadv:
>Doesn't cover all set of inputs.
>doesn't combine all possible combination

ECP

Equivalence Class Partitioning :

1.As the name suggests that the data is divided into such a
way that same class will give same type of input.Like
Class1 is a combination of Valid inputs and Class2 is a
combination of Invalid inputs.

Disadv :
>Heuristic based method.
>Limited focus.
>No guide lines for choosing input.

Is This Answer Correct ?    0 Yes 1 No

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