Answer / swapna

#include <stdio.h>
#include <conio.h>
void main ( )
{
long a,b,c,i,n,j;
clrscr( );
printf ("\n Enter the number to print fibnocci
prime number\t");
scanf ("%ld",&n);
a=0;
b=1;
for (i=1; i<n; i++)
{
c=a+b;
a=b;
b=c;
printf ("\n fibnoci series is %ld\t",c);
for(j=2;j<c;j++)
{
if(c%j==0)
break;
}
if(c==j)
printf(" prime number is %ld\t",c);
}
getch();
}

Answer / rajesh kumar s

int main()
{
int f=0,s=1,t=1,n,fl;
printf("enter the limit\t:");
scanf("%d",&n);
printf("\nfirst %d prime fibonacci numbers
are\n",n);
while(n)
{
fl=0;
fl=prime(f);
if(f>1 && fl==1)
{
printf("%d\t",f);
n=n-1;
}
s=t;
t=f;
f=s+t;
}
}

int prime(int x)
{
int i,f=0;
for(i=2;i<=x/2;i++)
{
if(x%i==0)
{
f=1;
break;
}
}
if(f==0)
{
return 1;
}
else
return 0;

}

Answer / ruchi

#include<stdio.h>
#include<conio.h>
int main()
{
int n,a=1,b,c=0,d=0,i,j;
printf("\nenter the number ");
scanf("%d",&n);
printf("\nThe fibbonacci prime numbers are ");
for(i=0;i<=n-1;i++)
{
b=c+a;
a=c;
c=b;
j=2;
while(j<=b-1)
{

if(b%j==0)
{

break;
}
j++;
}
if(j==b)
{
printf("\n%d",b);
}

}
getch();
}

Answer / abdifatah mohiadin adam

void main()
{
int x1,x2,x3,n,i;
x1=0;
x2=1;
printf("enter a value for n : ");
scanf("%d",&n);
printf("%d %d ",x1,x2);
for(i=3;i<=n;i++)
{
x3=x1+x2;
printf("%d ",x3);
x1=x2;
x2=x3;
}
}

Answer / subhabrato das

/*program to calculate lcm of 2 integers*/
#include"stdio.h"
#include"conio.h"
int lcm(int,int);
void main()
{
int a,b,lcm;
printf("Enter two integers...\n");
scanf("%d %d",&a,&b);
lcm=(a,b);
printf("\n\nLCM=%d",lcm);
}
int lcm(int a,int b)
{
int lcm;
int i=1;
while(1)
{
r=a*i;
if(r%b==0)
{
return r;
}
i++
}
}

Answer / jagannath

#include<stdio.h>
#include<conio.h>

int main()
{
int f=0,s=1,t=1,n,fl;
printf("enter the limit\t:");
scanf("%d",&n);
printf("\nfirst %d prime fibonacci numbers
are\n",n);
while(n)
{
fl=0;
fl=prime(f);
if(f>1 && fl==1)
{
printf("%d\t",f);
n=n-1;
}
s=t;
t=f;
f=s+t;
}
}

int prime(int x)
{
int i,f=0;
for(i=2;i<=x/2;i++)
{
if(x%i==0)
{
f=1;
break;
}
}
if(f==0)
{
return 1;
}
else
return 0;

}

Answer / nirupam mondal

#include <stdio.h>
void main ( )
{
long a,b,temp,i,n,j;
printf ("Enter the limit upto which you wantto print the fibonacci series : ");
scanf ("%ld",&n);
a=0;
b=1;
for (i=1; i<n; i++)
{
printf ("
%ld ",temp);
temp=a+b;
a=b;
b=temp;
for(j=2;j<temp;j++)
{
if(temp%j==0)
break;
}
if(temp==j)
printf(" The corresponding prime numbers of the series are : %ld ",temp);
}
}

Answer / yagneswara babu

void main()
{
int x1,x2,x3,n,i;
x1=0;
x2=1;
printf("enter a value for n : ");
scanf("%d",&n);
printf("%d %d ",x1,x2);
for(i=3;i<=n;i++)
{
x3=x1+x2;
printf("%d ",x3);
x1=x2;
x2=x3;
}
}

Answer / kamlesh shewar

enter a value for n :
7
0 1 1 2 3 5 8

Answer / rose

void main()
{
int x1,x2,x3,i,n;
x1=-1;
x2=1;
printf("enter the value for n :");
scanf("%d",&n);
print
for(i=0;i<n;i++)
{
x3=x1+x2;

if((x3 mod 2)!=0)
{
printf("%d ",x3)
}
x1=x2;
x2=x3;
}

}

what does ‘segmentation violation’ mean?

1 Answers  

If we have an array of Interger values, find out a sub array which has a maximum value of the array and start and end positions of the array..The sub array must be contiguious. Take the start add to be 4000. For Ex if we have an array arr[] = {-1,-2,-5,9,4,3,-6,8,7,6,5,-3} here the sub array of max would be {8,7,6,5} coz the sum of max contiguous array is 8+7+6+5 = 26.The start and end position is 4014(8) and 4020(5).

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