if ENTERED FIVE DIGITS DESIGN A PROGRAM THAT WILL FIND
CORRESPONDING VALUE FROM ASCII TABLE
Answer / vignesh1988i
since it is given as digits, lets assume that we take only
integers.
#include<stdio.h>
#include<conio.h>
void main()
{
int n,a[20],count=0;
printf("enter th number :");
scanf("%d",&n);
for(int i=0;n>0;i++)
{
a[i]=n%10;
n=n/10;
count++;
}
for(i=0;i<count;i++)
{
printf("%c",a[i]);
}
getch();
}
this will be the logic , i think so.....!
| Is This Answer Correct ? | 0 Yes | 1 No |
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2)#include<iostream.h> main() { printf("Hello World"); } the program prints Hello World without changing main() the o/p should be intialisation Hello World Desruct the changes should be a)iostream operator<<(iostream os, char*s) os<<'intialisation'<<(Hello World)<<Destruct b) c) d)none of the above
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can please someone teach me how to create this program using while statement.. this is the output should look like 0 2 4 6 8 10 -thanks.. :) need it asap...
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Question 1: You want to conduct a survey within your classroom, on the quality of canteen’s food. You ask each of your class fellows to rank the quality of food between 1 and 5 (1 representing excellent quality and 5 representing worst quality). During the survey, you make a list containing the roll# of student and the opinion given by that student. The list can be as follow Roll # Opinion 234 1 235 1 236 5 237 1 238 2 239 3 240 5 241 5 242 1 To get the results of the survey, you need to determine the frequency of each opinion value. The frequency of an opinion is determined by counting the number of students giving that opinion. For example, for the above list the frequency of opinion value 1 is 4 and frequency of opinion value 4 is 0. After getting the frequency of each opinion, you can easily judge about the quality of the food by seeing through the frequency of each opinion. You need to develop a program to calculate the results of this survey. The program inputs the opinion of 50 students and counts the frequency of each opinion. It then displays a report showing the frequency of each opinion. Sample output: Opinion Frequency Remarks 1 5 Excellent 2 10 Good 3 15 Normal 4 10 Bad 5 10 Really bad
int array[]={1,2,3,4,5,6,7,8}; #define SIZE (sizeof(array)/sizeof(int)) main() { if(-1<=SIZE) printf("1"); else printf("2"); }