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In a certain department store, which has four sizes of a
specific shirt, there are 1/3 as many small shirts as medium
shirts, and 1/2 as many large shirts as small shirts. If
there are as many x-large shirts as large shirts, what
percent of the shirts in the store are medium?
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Answer / sunil jha
S=M/3
L= S/2 = (M/3)*1/2= M/6
XL= L = M/6
S+M+L+XL=100
M/3 + M + M/6 + M/6 = 100
10M/6=100
M=60
| Is This Answer Correct ? | 17 Yes | 2 No |
Answer / dhruv
s=m/3;
l=s/2;
xl=s/2;
now,
s+m+l+xl=100;
m/3+m+m/6+m/6=100;
m=60%
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / sundar
let no. of small shirts = a
let no. of medium shirts = b
let no. of large shirts = c
let no. of x-large shirts = d
b = a/3
a = c/2
d = c
a=c/2
b=c/6
d=c
total no of shirts = a+b+c+d = c/2+c/6+c+c = 8c/3
%medium =(c/6)/(8c/3)*100 = 25%
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / raghu
@above...
answer is 25%
can u explain,how the answer is 25%...
| Is This Answer Correct ? | 0 Yes | 4 No |
Answer / mohitkuldeep
let no. of small shirts = a
let no. of medium shirts = b
let no. of large shirts = c
let no. of x-large shirts = d
b = a/3
a = c/2
d = a+b+c
=>
a = c/2
b = c/6
d = c/2 + c/6 +c
= 5c/3
total shirts = 5c/6 + c/2 + c/6 + c = 10c/3
%c = (c/(10c/3))*100 = 30% ans
| Is This Answer Correct ? | 1 Yes | 8 No |
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