Answer / arun kumar k s

select Distinct Top 2 Salary from EMP order by Salary desc

Answer / naren

select max(salary) as salary1 from employee where salary <
select max(salary) as salary2 from employee

Answer / raja.p

Find The 4 Top Salary in a Company
----------------------------------

CREATE TABLE EMPLOYEE2 (NAME VARCHAR2(20), SALARY NUMBER) ;

CREATE TABLE employee2 (
name char(20),
salary float);
INSERT INTO employee2 VALUES (
'Raja',
10000);
INSERT INTO employee2 VALUES (
'Arithas',
10000);
INSERT INTO employee2 VALUES (
'Balaji',
12000);
INSERT INTO employee2 VALUES (
'Vairam',
13000);
INSERT INTO employee2 VALUES (
'Muthu Krishnan',
14000);
INSERT INTO employee2 VALUES (
'Muthu Kumar',
15000);
INSERT INTO employee2 VALUES (
'Ramesh',
9000);

select e.name,e.salary from Employee2 e where 4>(select
count(Distinct
d.salary)from employee2 d where d.salary>e.salary) order by
e.salary desc;

Answer / ranjeet kumar shrivastava

select * from tbl_htl_cntry e where 2>=(select
count(distinct salary) from tbl_htl_cntry where
e.salary<=salary)

it is aslo working syntax.
ranjeetvasu@rediffmail.com

Answer / suhail qaiser

select top 2 salary from emp order by salary desc

Answer / suhail qaiser

or if u want 2nd highest then write this query

select Top 1 salary from ( select top 2 salary from
emp_table order by salary desc)temptable order by salary
asc.

Answer / sums

Step1:
Create the "Salary" table,

Create table Salary
( Design_name varchar(20),
Basic_Sal int)

Step2:
Insert the values into "Salary" table,

Insert into Salary values('Office_Boy',4000)
Go
Insert into Salary values('Clerk',5000)
Go
Insert into Salary values('Head_Clerk',6000)
Go
Insert into Salary values('Accountant',7000)
Go
Insert into Salary values('Manager',8000)
Go
Insert into Salary values('PA',9000)
Go
Insert into Salary values('GM',10000)

Step3:
Write the Query aganist "Salary" table to find 'N'th
Maximum Basic Salary.

Query:

Select * from Salary s1 where (N =(select count(distinct
(s2.Basic_Sal)) from Salary s2
where s2.Basic_Sal>=s1.Basic_Sal))

N=1 --> Finds the first maximum Basic_sal
N=2 --> Finds the second maximum Basic_sal
N=3 --> Finds the Third maximum Basic_sal
.
.
.
N='N'--> Finds the 'N'th maximum Basic_sal

To find '2' maximum:

Select * from Salary s1 where (2=(select count(distinct
(s2.Basic_Sal)) from Salary s2
where s2.Basic_Sal>=s1.Basic_Sal))

Output:

Design_name Basic_sal

PA 9000

Answer / pari

select max(sal) from emp
where sal !=(select max(sal) from emp);

Answer / srinivas

select e1.sal from emp e1 where 2=(select count(distnct
(e2.sal) from emp e2 where e2.sal>=e1.sal)

Answer / saravanan p

select distinct top 2 salary from employee order by salary
desc

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