In a team of 12 persons, 1/3 are women and 2/3 are men. To
obtain a team with 20% women how many men should be hired?
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Answer / andal
12(1/3) = 4 so women = 4
==>men = 12-4 = 8
if team needs 20% of women then men Will be 80%
consider u want to hire "x" men
so,
(12+x)(80/100) = 8 + x
so, x= 8
| Is This Answer Correct ? | 23 Yes | 0 No |
Answer / papun_satyajit
Women 4
If 4 is 20%
Then 80% is 4*4=16
Men 16
now men available = 12-4 = 8
So more men required = 16 - 6 =8
ANS:8
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / anil menon
total women=1/3*12 = 4 => rest 8 is men.
Let A be total team strength.
so A * 20% = 4 (since women number is constant)
therefore A = 4/(20%)= 20
men to be hired = 20-8 = 12
| Is This Answer Correct ? | 10 Yes | 5 No |
Answer / yours lovingly
for 2 women 8 men are nessary to become 20%
here women are constant i.e. 4 so another 2 women 8 more
men is required to become total 20%
2/10=20%
4/20=20%
| Is This Answer Correct ? | 4 Yes | 0 No |
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