Answer / jai

01 rec1.
02 a pic x(6) == 6
02 b redefines a. == 6
03 c occus 6 times pic 9. == 6
02 d occurs 6 times.
03 e pic x(5) ==30
03 f pic 999. ==18
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66

Answer / jayaprabhu

01 rec1.

02 a pic x(6)-------------------- 6 bytes
02 b redefines a.
03 c occurs 6 times pic 9.------ 6*1(pic 9 ie why we
have mul with 1 )------------------- 6 bytes
02 d occurs 6 times pic 9.------- (6*1) 6 bytes
03 e pic x(05)------------------- 5*6 =30 bytes
03 f pic 999. --------------------- 3*6=18

6
6
6
30
18

66

if you remove e f

18

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