WORKING-STORAGE SECTION.
01 A PIC X(3) VALUE 'ABC'
01 B PIC 9(3).
PROCEDURE DIVISION.
MOVE A TO B.
STOP RUN.
OUTPUT IS: AB3
WHY AND HOW THIS IS HAPPENING.
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Answer / mahe
You won't get AB3 as Output,Job will abend with SOC7 as you
r moving Character to Numeric variable
| Is This Answer Correct ? | 22 Yes | 4 No |
Answer / kamaldeep
I got AB3 as out put, when ever we are moving X(3) to 9(3) then 1st 2 bytes will be moved right(i.e. AB) but last byte will have '3' as C=+3
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / chandrababu
We will get 123 not AB3..why because
A = +1 J = -1
B = +2 K = -2
C = +3 L = -3
D = +4 M = -4
E = +5 N = -5
F = +6 O = -6
G = +7 P = -7
H = +8 Q = -8
I = +9 R = -9
So will get 123 for ABC..
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / velu
Exactly maha!!!!......actually we won't move the pic x(3)
to pic 9(3)(that's we can't move the alphabet to numeric
data type).....it should shows the abed...
| Is This Answer Correct ? | 1 Yes | 4 No |
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