How do you retrieve the second highest salary from a table?
Answers were Sorted based on User's Feedback
Answer / nashiinformaticssolutions
Using a subquery:
SELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
Using ROW_NUMBER():
SELECT salary
FROM (
SELECT salary, ROW_NUMBER() OVER (ORDER BY salary DESC) AS row_num
FROM employees
) ranked
WHERE row_num = 2;
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / glibwaresoftsolutions
Using a subquery:
SELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
Using ROW_NUMBER():
SELECT salary
FROM (
SELECT salary, ROW_NUMBER() OVER (ORDER BY salary DESC) AS row_num
FROM employees
) ranked
WHERE row_num = 2;
| Is This Answer Correct ? | 0 Yes | 0 No |
Using a subquery:
SELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
Using ROW_NUMBER():
SELECT salary
FROM (
SELECT salary, ROW_NUMBER() OVER (ORDER BY salary DESC) AS row_num
FROM employees
) ranked
WHERE row_num = 2;
| Is This Answer Correct ? | 0 Yes | 0 No |
Table name: T1, it has only one column. col1 ------ c b a b b b b d s a a t s Requirement: I need the following output from the above base table by using SQL query. col1 Cnt ----- ------- a 3 b 5 Others 5 Please help. Thanks Guru v.gurus@in.com
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