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x==2+2^(2/3)+2^(1/3) .Then what is the value of x^3-6X^2+x ?
here X^Y indicates X to the power of Y.
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Answer / sudheer
(x-2)^3==x^3-6x^2+12x-8
(x-2)^3==(2^(2/3)+2^(1/3))^3
therefore,by solving
Ans: x^3-6x^2+x== -8-5*2^(2/3)-5*2^(1/3)
| Is This Answer Correct ? | 5 Yes | 9 No |
Answer / chida
x= 2+2^(2/3)+2^(1/3)
=2{1+1^(2/3)+1^(1/3)}
=2(1+1+1)
=>x==6
So
the value of x^3-6X^2+x is
6^3-6.6^2+6
=6
| Is This Answer Correct ? | 9 Yes | 23 No |
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