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x==2+2^(2/3)+2^(1/3) .Then what is the value of x^3-6X^2+x ?
here X^Y indicates X to the power of Y.
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Answer Posted / chida
x= 2+2^(2/3)+2^(1/3)
=2{1+1^(2/3)+1^(1/3)}
=2(1+1+1)
=>x==6
So
the value of x^3-6X^2+x is
6^3-6.6^2+6
=6
| Is This Answer Correct ? | 9 Yes | 23 No |
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