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Can anyone explain me these 3 techniques with an example?
1).Equalent Class Partision
2).Cause-Effect Graph analysis
3).Error Guessing.

Answers were Sorted based on User's Feedback



Can anyone explain me these 3 techniques with an example? 1).Equalent Class Partision 2).Cause-Ef..

Answer / sj1234

Consider any edit field which can accept values b/w 18-35.

Equivalence pertitioning In this method given i/p is
divided into number of equivalence classes.

From each equivalence class one i/p value is chosed for
testing.
Ex.Consider the above ex. edit field which accepts i/p
value b/w 18-35.
From the given range of i/p value we can form 3
equivalence classes.

i) Less than 18.
ii) Between 18-35.
iii) Greater than 35.

Take any value from three equivalence classes and test
them. example 6, 25,100

3) Error guessing.This depends on the tester experience,
domain knowledge, & common sense.
Ex:For the same above ex.i)23+,-34,5*,00,Blank,5o(Not
zero,O),etc.

4) Cause-Effect GraphCause Effect Graph: A Boolean graph
linking causes and effects

Is This Answer Correct ?    1 Yes 1 No

Can anyone explain me these 3 techniques with an example? 1).Equalent Class Partision 2).Cause-Ef..

Answer / avinash

Shraini you are wrong. Equivalence partitioning is a software testing technique that divides the input data of a software unit into partition of data from which test cases can be derived. In principle, test cases are designed to cover each partition at least once. This technique tries to define test case that uncovers classes of errors, thereby reducing the total number of test cases that must be developed.

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Can anyone explain me these 3 techniques with an example? 1).Equalent Class Partision 2).Cause-Ef..

Answer / shraini

what you explained about equalent class partition is not
correct.that is all about boundry value testing.testing the
size and range values of an object.
According to my knowledge equalent class partition is
testing the type of objects,ex: in a drop down box for
gender (Male /female).
If I am wrong please correct me.

Is This Answer Correct ?    0 Yes 2 No

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