Answer / a.jyothsna

select a.sal
from emp a
where 3=(select distinct(count(b.sal))
from emp b
where a.sal<=b.sal)

Answer / kaushal kassi

select distinct a.sal
from employee a
where 3=(select count(distinct b.sal)
from employee b
where a.sal<=b.sal)

Answer / srikanth

select q.sal
from emp q
where 3=(select distinct(count(b.sal))
from emp b
where q.sal<=b.sal)

Answer / karna

Hi Friends,

to get the nth highest value of a column in a table,please
use the below simple query

select min(column) from table where column in(select top n
column from table)

any queries,mail me at karun84@gmail.com

Answer / karna

Hi Friends,

sorry,last answer was wrong.
I have changed the query,check now

to get the nth highest value of a column in a table,please
use the below simple query

select min(column) from table where column in(select top n
column from table order by desc)

any queries,mail me at karun84@gmail.com

Answer / surendra kumar dattatrey

Select * from Emp where Salary =
(Select max(Salary) from Emp where Salary <
(Select max(Salary) from Emp where Salary <
(Select max(Salary) from Emp where Salary <.....N))))

Answer / abhay

select distinct(sal) from emp a where 3=(select
count(distinct(sal) from emp b where a.sal<=b.sal);


somebody tell me he logic....!

Answer / sachin

select distinct(sal) from employee order by sal desc limit 2,1;

Answer / anjali

select min(column_name) from table where column in(select
top n
column_name from table order by column_name desc)

Answer / amit singh

Empsal table data
700
500
100
900
400
200
600
750


query to find second highest salary from table Empsal

mysql>select distinct(max(e.salary)) from Empsal e
>where e.salary in(
>select e1.salary from Empsal e1 where e1.salary<
(select max(salary) from Empsal));

Output=750



query to find third highest salary from table Empsal


mysql>select distinct(max(e.salary)) from Empsal e
>where e.salary in(
>select e1.salary from Empsal e1 where e1.salary<
>(select max(e1.salary) from Empsal e1
>where e1.salary IN(
>select e2.salary from Empsal e2 where
>e2.salary<(select max(salary) from Empsal))));
Output=700

RUN THE QUERY THEN ARG
amitsing2008@gmail.com(amit is back)

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