What is the output of the program given below #include<stdio.h>

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What is the output of the program given below

#include<stdio.h>
main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}

Question Posted / rajesh

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What is the output of the program given below #include<stdio.h> main() { ..

Answer / sh college,thevara

-128

Is This Answer Correct ?

31 Yes

8 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / sharan

#include<stdio.h>
main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}

Here the CATCH is semicolon after for
so maximum positive value for the signed char is 127.
Hence it loops 127 times after that value of i wraps to
negative value that is -128.

Thus it prints -128.

Is This Answer Correct ?

11 Yes

1 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / rani

output is

-128

Is This Answer Correct ?

11 Yes

3 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / karan

it will display the garbage value bcoz there is semicolon
at end of the for loop which will be
-128

Is This Answer Correct ?

3 Yes

0 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / gajanandon

after for there is semicolon...means empty statement. So no
effect of printf.
so for runs till i (char value) increments in positive
direction and terminates once it exceeds 127 (char
limitation).
Hence finally printf will execute and then prints -128.

Is This Answer Correct ?

3 Yes

0 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / stuti

Is This Answer Correct ?

2 Yes

0 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / aryan

-128

Is This Answer Correct ?

2 Yes

0 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / rekha

It will print 0 to 127

Is This Answer Correct ?

6 Yes

6 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / prasanna kumar [cse dept. kln

i think the program will give the output as 0 or null....
because i=0 is in int datatype but in this program it is
declared as character datatype so it will give the output as
0 or null and it will goes for only one time after wards it
will incremented and goes infinitely....

Is This Answer Correct ?

0 Yes

0 No

What is the output of the program given below #include<stdio.h> main() { ..

Answer / akash dhal

initialized with 0
in for loop ist time condition satisfied so print 0,like
this 127 will be printed .as it is a signed no. so 127+1 is
-128 so condition false come out of the loop.

Is This Answer Correct ?

0 Yes

0 No

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