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What is the output for the following program
#include<stdio.h>
main()
{
char a[5][5],flag;
a[0][0]='A';
flag=((a==*a)&&(*a==a[0]));
printf("%d\n",flag);
}
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Answer / sri
output is 1 but this prg display 2 warning (ie) Nonportable
pointer comparsion
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / vignesh1988i
FLAG WILL give zero.....
because a refers to the 2D array's base address, *a refers to the value at the 0th row and 0th column.... so this address will not match the ascii value of the char 'A'.... so however it is logical AND so, the value is 0.........
thank u
| Is This Answer Correct ? | 4 Yes | 1 No |
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