what will be the output:
main(){char ch;int a=10;printf("%d",ch);}
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Answer / bharath s
The answer is Garbage value...
The answer willbe lik -113...Depending upon the compailer
If we declare as..
static char ch;
Then Answer is 0.....
| Is This Answer Correct ? | 21 Yes | 0 No |
Answer / paul
It'll give a warnin tat "a is never used...If u Continue
executing...it will the memory addres that is currently
used.
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / sadasiva
It gives compilation warning but not Error.
While running ,gives Run time check error and prints some
garbage value.
| Is This Answer Correct ? | 8 Yes | 1 No |
Answer / anu
I think it will not give any error and it will print some
garbage value.
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / manju
The answer is garbage value because ch is not initialised
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / sirajuddin
variable ch is of character type and nothing is assigned
to it where as 'a' is of interger type.
In the printf statement we are placing variable 'ch' along
with %d which will display a garbage value.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / sulagna samapika
what will be the output of printf("%d")
ans-
the outpot is 0
| Is This Answer Correct ? | 2 Yes | 0 No |
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