palindrome for strings and numbers----Can anybody do the
prog?
Answers were Sorted based on User's Feedback
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
char a[20],b[20];
int i;
clrscr();
printf("\n Enter the Number or String to find Palindrome");
scanf("%s",a);
strcpy(b,a);
strrev(a);
if(strcmp(a,b)==0)
{
printf("\n Entered data is Palindrome\n");
}
else
{
printf("\n Entered data is not a Palindrome\n");
}
getch();
}
Is This Answer Correct ? | 9 Yes | 2 No |
Answer / subbu
/*some corrections to above solution*/
#include<stdio.h>
#include<conio.h>
void main()
{
int n,r,temp;
int s=0;
printf("enter the number");
scanf("%d",&n);
temp=n;
while(temp>0)
{
r=temp%10;
s=s*10+r;
temp=temp/10;
}
if(n==s)
printf("number is pallindrome");
else
printf("not pallindrome");
getch();
}
Is This Answer Correct ? | 10 Yes | 5 No |
Answer / dally
#include<stdio.h>
int main()
{
int n,sum=0,temp;
printf("Enter nuber\n");
scanf("%d",&n);
temp = n;
while(n>1)
{
n = n%10;
sum = n + sum*10;
n = n / 10;
}
if(temp == sum)
printf("Given number is polindram\n");
else
printf("Given number is not polindram\n");
}
Is This Answer Correct ? | 4 Yes | 2 No |
Answer / arup bhattacharya
#include<stdio.h>
#include<conio.h>
void main()
{
int n,r,temp;
int s=0;
clrscr();
printf("enter the number");
scanf("%d",&n);
temp=n;
while(temp>0)
{
r=temp%10;
s=s*10+r;
temp=temp/10;
}
if(n==temp)
printf(number is pallindrome");
else
printf("not pallindrome");
getch();
}
Is This Answer Correct ? | 9 Yes | 8 No |
//the palindrome for string can also be written as below,
without using inbuilt functions.
void main()
{
char str[10];
int flag = 0;
int i , j;
puts("ENTER THE STRING");
fflush(stdin);
gets(str);
for(i = 0 ; str[i] != '\0' ; i++);
i--;
for(j = 0 ; j<i ; j++ , i--)
{
if(str[j] == str[i])
flag = 1;
else
{
flag = 0;
break;
}
}
if(flag == 1)
puts("STRING IS A PALINDROME");
else
puts("STRING IS NOT A PALINDROME");
}
Is This Answer Correct ? | 4 Yes | 3 No |
Answer / sree
#include<stdio.h>
void main
{
int n,t,d,r;
printf("Enter the number:");
scanf("%d",&n);
t=n;
while(n>=1)
{
d=n%10;
r=(r*10)+d;
n=n/10;
}
if(t==r)
printf("Palindrome");
else
printf("Not a palindrome");
}
Is This Answer Correct ? | 3 Yes | 3 No |
input may any number except 1,output will always 1.. conditions only one variable should be declare,don't use operators,expressions,array,structure
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