Write an implementation of “float stringToFloat(char *str).”
The code should be simple, and not require more than the
basic operators (if, for, math operators, etc.).
• Assumptions
• Don’t worry about overflow or underflow
• Stop at the 1st invalid character and return the number
you have converted till then, if the 1st character is
invalid return 0
• Don’t worry about exponential (e.g. 1e10), instead you
should treat ‘e’ as an invalid character
• Write it like real code, e.g. do error checking
• Go though the string only once
• Examples
• “1.23” should return 1.23
• “1a” should return 1
• “a”should return 0
- 6 Answers
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Answer / piyush sharma
#include<iostream>
using namespace std;
int main()
{
char* str = "36.78sg67";
char ch;
int decimal_pt = 0;
int dec_count = 0;
float val = 0.0;
for( int i=0; str[i]!='\0'; i++ )
{
ch = str[i];
if( ch == '.' )
{
decimal_pt = 1;
continue;
}
if( !(ch>=48 && ch<=57) )
break;
val = val*10 + ch-48;
if( decimal_pt == 1 )
dec_count++;
}
for( int i=0; i<dec_count; i++ )
val = val/10;
cout << val << endl;
system("pause");
return 0;
}
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / piyush sharma
float stringToFloat(char *str)
{
char ch;
int decimal_pt = 0;
int dec_count = 0;
float val = 0.0;
for( int i=0; str[i]!='\0'; i++ )
{
ch = str[i];
if( ch == '.' )
{
decimal_pt = 1;
continue;
}
if( !(ch>=48 && ch<=57) )
break;
val = val*10 + ch-48;
if( decimal_pt == 1 )
dec_count++;
}
for( int i=0; i<dec_count; i++ )
val = val/10;
return val;
}
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / nikita
The above two solutions do not take care of the numberes
after the decimal.
for eg; "123.78" would return 123.0000 instead it should
return 123.78.
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / c l
float stringToFloat(char *str)
{
float retVal = 0;
float devisor = 1;
int strSize = sizeof(str);
int multiplySign = 1;
bool foundDecimal = false;
/* check for non empty char array */
if (strSize > 0 )
{
if (str[0] >= '0' && str[0] <= '9')
retVal = str[0] - '0';
else if (str[0] == '.')
foundDecimal = true;
else if (str[0] == '-')
mulitplySign = -1;
else if (str[0] == '+')
; /* NOP */
else
return retVal;
for (i = 1; i < strSize; i++)
{
if (str[i] >= '0' && str[i] <= '9')
{
retValue = retValue*10 + str[i] - '0';
if (foundDecimal)
divisor = divisor * 10;
}
else if (str[i] == '.')
if(foundDecimal) /* 2nd '.', err */
break;
else
foundDecimal = true;
else /* anything else is err cond */
break;
}
return multiplySign * retVal / divisor;
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / fernando
If I have character buffer with many floats and want to
separate it as I do?
Example:
for (uint8_t i = 0; i < n; i++)
{
buf [i]; 25.45, 26.54,...
}
buf[0]=
buf[1]=
.
.
.
buf[n]=
Thanks.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / nikita
#include<stdio.h>
#include<string.h>
int main()
{
int i = 0;
float result = 0;
int dec_count = 0;
int isDec = 0;
char* str = "123.76bg";
while(str[i])
{
if(str[i] == '.')
{
isDec = 1;
i++;
}
if((str[i]>=48) && (str[i]<=57))
{
result = result * 10;
result = result + (str[i++] - '0');
}
else
{
break;
}
if(isDec == 1)
{
dec_count++;
}
}
printf("\nThe result is: %f", result);
for(i=0; i<dec_count; i++)
{
result = result / 10;
}
printf("\nThe result is: %f", result);
return 0;
}
| Is This Answer Correct ? | 1 Yes | 2 No |
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