input may any number except 1,output will always 1.. conditions only one variab

input may any number except 1,output will always 1..
conditions only one variable should be declare,don't use
operators,expressions,array,structure

Question Posted / karna

Answers were Sorted based on User's Feedback

input may any number except 1,output will always 1.. conditions only one variable should be declare..

Answer / kesavalu

#include<stdio.h>
#include<conio.h>
main()
{
int d;
printf("enter any no except 1");
scanf("%d",&d);
clrscr();
printf("1");
getch();
}

Is This Answer Correct ?

9 Yes

2 No

input may any number except 1,output will always 1.. conditions only one variable should be declare..

Answer / nila

#include<stdio.h>
#include<conio.h>
main()
{
int a;
printf("Enter the number:");
scanf("%d",&a);
printf("1");
getch();
}

Is This Answer Correct ?

3 Yes

1 No

input may any number except 1,output will always 1.. conditions only one variable should be declare..

#include<stdio.h>
main()

{int a;
printf("%d",scanf("%d",&a));
}

Is This Answer Correct ?

9 Yes

8 No

input may any number except 1,output will always 1.. conditions only one variable should be declare..

Answer / dana

#include<stdio.h>
#include<conio.h>
main()
{
int x;
printf{"enter the num ",x);
scanf("%d",&x);
if(x!=1)
printf("1");
else
printf(" ");
}

Is This Answer Correct ?

0 Yes

0 No