There are two candles of equal lengths and of different
thickness. The thicker one lasts of six hours. The thinner
2 hours less than the thicker one. Ramesh lights the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. How
long ago did Ramesh light the two candles .
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Answer / sasidhar
Let the initial height of the candles be equal to 1 unit. If the candles have burned for x hours for the first candle to be half the height of the second candle, we can write
(x/4)=((4-x)/4)
(x/6)=((6-x)/6)
Height of the first candle left = (1/2)Height of the second candle
((4-x)/4)=((6-x)/6)
x=1 hr
so ramesh light the candles before=total length of thin candle-remaining length of thin candle)=4-1=3hr
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / sarala
1 hour answer,how to know correct or wrong is the my answer
| Is This Answer Correct ? | 2 Yes | 14 No |
Answer / sandhya
let L be the length of candles and t be the time(hrs) he
litted the candles.
after t hrs the propotions of loss is same...
so..
for thicker 6-t/4-t =(L-x/2)/(L-x/4)
then u get t as 2Hrs
| Is This Answer Correct ? | 14 Yes | 29 No |
Answer / palaniappan
let x be time at witch RAMESH lighted the candles
since thicker one last for 6hrs &thinner for 2hrs lesser
than thicker
so,
6=2x
x=6/2
=>x=3hrs
| Is This Answer Correct ? | 22 Yes | 52 No |
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