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There are two candles of equal lengths and of different
thickness. The thicker one lasts of six hours. The thinner
2 hours less than the thicker one. Ramesh lights the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. How
long ago did Ramesh light the two candles .
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Answer Posted / sasidhar
Let the initial height of the candles be equal to 1 unit. If the candles have burned for x hours for the first candle to be half the height of the second candle, we can write
(x/4)=((4-x)/4)
(x/6)=((6-x)/6)
Height of the first candle left = (1/2)Height of the second candle
((4-x)/4)=((6-x)/6)
x=1 hr
so ramesh light the candles before=total length of thin candle-remaining length of thin candle)=4-1=3hr
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