A cow is tethered in the middle of a field with a 14 feet
long rope. If the cow grazes 100 sq feet per day
approximately. What time will be taken by the cow to graze
the grazeable area of the field?
(a) 2 days
(b) 18 days
(c) 24 days
(d) 6 days
(e) None of these
Answers were Sorted based on User's Feedback
Answer / sabarish
area consumed = pi*14*14 = 615.44 sq.ft
rate of consumption = 100sq.ft per day
No of days = 615.44/100=6.1
rounding off to 6 days approx..
(not sure)
| Is This Answer Correct ? | 28 Yes | 7 No |
Answer / venkat
area = πr2
area = 3.14x14x14
area = 3.14x196
area = 615.44...
time taken = 615.44/100
time taken = 6.1 days
(i.e) 100 feet per day ...
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / niveditha
Area of the field grazed = [22/7*14*14]sq.ft. = 616 sq.ft.
Number of days taken to graze the field = 616/100 days
=> 6 days(approx.)
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / phani madhav
We do not know what exactly the total area is so by
assuming as 14 feet the total area as a square then it
comes to 196 sqft and as the grazes 100 sqft per day then
the balance 96 sqft it should graze the next day. Rounding
off to the second day we can treat the answer as 2 days.
| Is This Answer Correct ? | 2 Yes | 14 No |
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